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3 years ago

13

Please help me with these thanks!! :)

1 answer:

solniwko [45]3 years ago

8 0

Answer:

this one is rational and real :)

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avanturin [10]

Given :-

$(9^{2} )^{-1/3}$

To Find :-

To solve the expression .

Solution :-

Given expression to us is ,

$(9^{2} )^{-1/3}$

We know that ,

$9 = 3^2$

So our expression becomes ,

$\{ (3^2)^2\}^{\frac{-1}{3}}$

And , $(a^m)^n =a^{mn}$ . Using this ,

$(3^4)^{\frac{-1}{3}}$

Again using the same law ,

$3^{\frac{-4}{3}}$

We know that , $a^{-m}=\frac{1}{a^m}$ . Therefore ,

$(3^{-4})^{\frac{1}{3}}$

$\\\bigg( \dfrac{1}{3^4}\bigg)^{1/3}$

$\\ \dfrac{1}{\sqrt[3]{3^4}}$

Simplify ,

$\dfrac{1}{3\sqrt[3]{3}}$

This is the simplified expression.

<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>

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2 years ago

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