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k0ka [10]
3 years ago
7

How to solve this question

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0
8.83176088663 is the answer
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Y=mx+b is the formula you use to find the answer
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3 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
Let g (2) = 22 – 5 and h (2) = 22 +1.<br> Find (g+h) (2)
hjlf

Answer:

23 + 17 = 40 :)

8 0
2 years ago
Which graphs have a positive average rate of change?
adelina 88 [10]

Answer:

Step-by-step explanation:

In general, graphs that go from lower left to upper right have a positive slope (think of it as going up the stairs...positive), and graphs that go from upper left to lower right have a negative slope (think of it as going down the stairs...negative).  I don't see graphs here but use this general idea and you'll be fine.  Of course, this applies to graphs of lines of the form y = mx + b.

4 0
3 years ago
Δ ABC is isosceles with m∠B ≅ m∠C. If m∠A = 100°, m∠B = (12x + 4)°, and m∠C = (14x - 2)°, find x.
natita [175]

Answer:

x = 3

Step-by-step explanation:

Since ΔABC is isosceles with ∠A = 100° then the base angles are equal, that is

∠C = ∠B , that is

14x - 2 = 12x + 4 ( subtract 12x from both sides )

2x - 2 = 4 ( add 2 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

6 0
3 years ago
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