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zlopas [31]
3 years ago
10

Solve the equation 1) 4.3^x+1 = 27+9^x 2) 3^x+5= 3^x+3+8/3

Mathematics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

Step-by-step explanation:

4*3^x+1=27+(3^2)^x

(3^2)^x=(3^x)^2

3^x=t

4t+1=27+t^2

t^2-4t+27-1=0

t^2-4t+26=0

delta=4^2-4*1*26=16-84=-68<0

the  equation has not real solutions

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A cylinder with radius 3 feet and height 5 feet is shown.
Leviafan [203]

Answer:

The volume of the cylinder is <u>141.23 cubic feet </u>

Step by step explanation :

<u>Given</u>-

  • Radius of cylinder = 3 feet
  • Height of cylinder = 5 feet

Now, we know that

<h3>\boxed {\mathfrak \red{ volume \: of \: cylinder = \pi {r}^{2} h}}</h3>

where, r is the radius of the cylinder & h is the height of the cylinder.

Now,

Volume of the cylinder = \frac{22}{7}  \times  {3}^{2}  \times 5

=  \frac{22}{7}  \times 3 \times 3 \times 5

<h3>=   \frac{990}{7}</h3>

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2 years ago
A sphere is inscribed in a cylinder. The surface area of the sphere and the lateral area of the cylinder are equal. true or fals
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The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

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Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

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So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

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