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zlopas [31]
3 years ago
10

Solve the equation 1) 4.3^x+1 = 27+9^x 2) 3^x+5= 3^x+3+8/3

Mathematics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

Step-by-step explanation:

4*3^x+1=27+(3^2)^x

(3^2)^x=(3^x)^2

3^x=t

4t+1=27+t^2

t^2-4t+27-1=0

t^2-4t+26=0

delta=4^2-4*1*26=16-84=-68<0

the  equation has not real solutions

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larisa86 [58]

Answer: $8.19

Step-by-step explanation: Times 565 by 1.45% and that's what you get.

6 0
2 years ago
Read 2 more answers
(Adding and Subtracting Polynomials)
andrey2020 [161]

Adding and subtracting big polynomials like these are pretty easy. You just need to combine like terms. For example:

1.)

{5x}^{2}  +  {3x}^{2}  =  {8x}^{2}

2.)

({3x}^{2}  + 5xy) + (7xy + 2) =

{3x}^{2} + 12xy + 2

(The 3x^2 and the 2 stay intact while the 5xy and 7xy combine together)

All you have to do is combine the numbers that have the same powers of x and y with each other. x^2 will combine with x^2 and xy^2 wil combine with xy^2 exc. If there is no other number with the same x and y's, then you just leave it as it is in the answer.

Now with the original question, I see a -9xy^3, and thats gonna combine with the 3xy^3 in the second polynomial and the 2xy^3 in the third one.

- 9x {y}^{3}  + 3x {y}^{3}  + 2x {y}^{3} = \\  - 4x {y}^{3}

So far we have -4xy^3, the next term is going to be a -9x^4y^3, and that's gonna combine with the 3x^4y^3 in the third one.

- 9 {x}^{4} {y}^{3}  + 3 {x}^{4}  {y}^{3}  =  - 6{x}^{4}  {y}^{3}

We now finished adding the like terms that were in the first polynomial, we will move onto the second polynomial. The first term in this one is 3xy^3, in which we already added in the first step. At this point, it doesn't look like there are any other terms that have the same x and y behind them. So we can move on and write the final answer:

- 4x {y}^{3} - 6 {x}^{4} {y}^{3}  + 7 {y}^{4}  \\ - 8 {x}^{4} {y}^{4}

(All on the same line of course)

Also, for your second question, the order does not matter in which you write the terms. I could write the 7y^4 behind the -8x^4y^4 and it would still be the same answer.

If you have any other questions let me know :) while I double check my work.

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3 years ago
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= -2

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Add 6 to both sides.
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Divide both sides by 5.
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