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3 years ago

8

In Jennifer’s anatomy and physiology class, her grade is determined by dropping the lowest score out of 10 tests and averaging t

he remaining 9 test scores. Jennifer has earned the following scores on the first 9 tests: 85%, 89%, 93%, 96%, 90%, 89%, 92%, 91%, and 82%. What does Jennifer need to earn on her 10th test in order to receive at least an 80% in the class? A. 80% B. 85% C. 90% D. Jennifer will receive at least an 80% in the class no matter what she gets on the 10th test.

2 answers:

mylen [45]3 years ago

7 0

The answer is d because you add all of them up and you get 807 then you divide by 9 and you get 89.6 and then you round and get 90

Sedbober [7]3 years ago

5 0

Answer is d she is already averaging over 89%

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Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

2 years ago

siniylev [52]

Answer:

179

Step-by-step explanation:

The total number of animals in the river was 632.

A herd of 187 elephants and 266 zebras left the river area.

Adding them up, the total number of animals that left the river area is:

187 + 266 = 453

Therefore, the total number of animals left at the river area is the subtraction for the animals that left the river area from the number of animals that were there initially:

632 - 453 = 179

3 0

2 years ago

HELP FAST PLEASE!!!

Alisiya [41]

Answer:

$y = -0.75x + 9.5$

Step-by-step explanation:

Equation of a circle is given as :

$(x-a)^{2} + (y-b)^2 = r^{2} \\(x-6)^{2} + (y-5)^2 = 4^{2}\\x^{2} - 12x + 36 + y^{2} -10y + 25 = 16\\x^{2} - 12x + y^{2} -10y + 45 = 0\\$

Take the derivative of the above with respect to x

$2x - 12 + 2y dy/dx - 10 dy/dy = 0\\\frac{dx}{dy} = \frac{6 - x}{y-5} \\At (2,8) dy/dx = (6-2)/(8-5) = 4/3\\dy/dx = 4/3\\The slope of the tangent to the circle, m = \frac{-1}{dy/dx} \\m = \frac{-1}{4/3}\\m= -0.75$

The equation of the tangent is given by :

$y - y_{1} = m(x - x_{1})\\ y - 8 = -0.75(x - 2)\\y - 8 = -0.75x + 1.5\\y = -0.75x + 9.5$

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3 years ago

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2 years ago

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Korvikt [17]

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