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liberstina [14]
3 years ago
7

Does anyone know what f(x)=-5x-1 when f(-7) i need help with this please.

Mathematics
1 answer:
vodomira [7]3 years ago
8 0

Answer:

f(-7) = 34

Step-by-step explanation:

If f(x) = -5x - 1, then . . .

f(x) = -5x - 1

f(-7) = -5(-7) - 1

       = 35 - 1

       = 34

. . . because in f(-7), the (-7) is the x-value you're supposed to use to find the value of the function.

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They are called relation symbols
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less than tells you that you must be less than, but not euqal to. example
 this thing must be less than 7 feet tall to fit under the doorway, it cannot be 7 feet or else it wont fit

equal to is an exact amount, nothing more or less
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less and greater than is nice since if you found a solution and you wanted to notate it, example
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3 0
3 years ago
Read 2 more answers
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

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Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

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M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

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M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

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Answer:

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