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DerKrebs [107]
3 years ago
5

The table below shows the results of a random sample of 160 teenagers. Based on the information given which of the following sta

tement are true? Select all that apply

Mathematics
2 answers:
Karolina [17]3 years ago
7 0

Answer:

I would say that it is all of them besides the 35% of the participants do not like to surf.

Sonja [21]3 years ago
3 0
<h2>Answer:</h2>

The correct statements are:

  •  66% of the participants were boys.
  • 80/105 of the boys like to surf.
  • 10/35 of the participants who do not like to surf were girls.
<h2>Step-by-step explanation:</h2>

A)

The total number of students who were studied= 160

Number of boys= 105

Hence, Percentage of boys is calculated as:

Percent\ Boys=\dfrac{105}{160}\times 100\\\\i.e.\\\\Percent\ Boys=\dfrac{1050}{16}\\\\\\Percent\ Boys=65.625\\\\which\ is\ approximately\ equal\ to:\\\\Percent\ Boys=66\%

B)

Number of students who like to surf=125

Hence,

Percent who like to surf is calculated as:

=\dfrac{125}{160}\times 100\\\\\\=\dfrac{1250}{16}\\\\=78.125\%

C)

Number of boys=105

and number of boys who like to surf=80

Hence, the proportion of boys who like to surf is:

80/105

D)

Number of people who do not like to surf=35

Number of girls who do not like to surf=10

Hence,the proportion of girls who do not like to surf is:

              10/35

E)

Proportion of boys who like to surf=80/105=0.76190

and proportion of boys who like to surf= 45/55=0.8181

Hence, the proportion of girls who like to surf are more than those of boys who like to surf.

(  Since,   0.8181 < 0.76190 )

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Expanded form for 48,243. (
Dima020 [189]
(4*10,000)+(8*1,000)+(2*100)+(4*10)+(3*1)

40,000+8,000+200+40+3=48,243

That is one way. You can also do this using exponential form!

Hope that helps

4 0
3 years ago
A baker had 1,128 cookies. She put them all in bags, with 24 cookies in each bag. What is the total number of bags that she used
Rainbow [258]
1,128 divided by 24 = 47 bags. To make sure this answer is right you can multiply 24 and 47 and you get 1,128
7 0
3 years ago
Anyone know any good sites for social study's?? Or for math?
pychu [463]

Answer:

no i do not lolololoololoooo9lololollLLLOLOl

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Here you go btidwill1862
alexandr1967 [171]

i looked it up

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7 0
3 years ago
Find the number of terms, n, in the arithmetic series whose first term is 13, the common difference is 7, and the sum is 2613.
siniylev [52]

Answer:

A

Step-by-step explanation:

Recall that the sum of an arithmetic series is given by:

\displaystyle S = \frac{n}{2}\left(a + x_n\right)

Where <em>n</em> is the number of terms, <em>a</em> is the first term, and <em>x</em>_<em>n</em> is the last term.

We know that the initial term <em>a</em> is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find <em>n</em>.

First, find the last term. Recall that the direct formula for an arithmetic sequence is given by:

x_n=a+d(n-1)

Since the initial term is 13 and the common difference is 7:

x_n=13+7(n-1)

Substitute:

\displaystyle S = \frac{n}{2}\left(a + (13+7(n-1)\right)

We are given that the initial term is 13 and the sum is 2613. Substitute:

\displaystyle (2613)=\frac{n}{2}((13)+(13+7(n-1)))

Solve for <em>n</em>. Multiply both sides by two and combine like terms:

5226 = n(26+7(n-1))

Distribute:

5226 = n (26+7n-7)

Simplify:

5226 = 7n^2+19n

Isolate the equation:

7n^2+19n-5226=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 7, <em>b</em> = 19, and <em>c</em> = -5226. Substitute:

\displaystyle x  =\frac{-(19)\pm\sqrt{(19)^2-4(7)(-5226)}}{2(7)}

Evaluate:

\displaystyle x = \frac{-19\pm\sqrt{146689}}{14} = \frac{-19\pm 383}{14}

Evaluate for each case:

\displaystyle x _ 1 = \frac{-19+383}{14} = 26\text{ or } x _ 2 = \frac{-19-383}{14}=-\frac{201}{7}

We can ignore the second solution since it is negative and non-natural.

Therefore, there are 26 terms in the arithmetic series.

Our answer is A.

6 0
3 years ago
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