What is the factored form of x^3-1

Mathematics

1 answer:

polet [3.4K]3 years ago

7 0

Answer:

the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

Step-by-step explanation:

We need to find factors of x^3 -1

$x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\$

So, the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

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If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

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Note: The hypotenuse is the longest side of a right triangle.

Word Problen

The legs are 21 blocks and 20 blocks because they are by the right angle. Use the Pythagorean theorem to find the diagonal path's length, which is the hypotenuse.

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