No, it’s a negative so no. it is before the 0 on a number line and the five is after which mean -15 is smaller
Answer:
Step-by-step explanation:
If we are looking for the time(s) that the ball is at a height of 15, we simply sub in a 15 for the height in the position equation and solve for t:
and

Factor this however you factor a quadratic in class to get
t = .59 seconds and t = .85 seconds.
This means that .59 seconds after the ball was thrown into the air it was 15 feet off the ground. Then the ball reached its max height, gravity took over, and began pulling it back down to earth. The ball passes the height of 15 feet again on its way down after .85 seconds.
Answer:
A and B
Step-by-step explanation:
A is correct because the three terms are x², 5<em>yz,</em> and -8.
B is 100% correct I guarantee it.
C is incorrect because ² is not a coefficient.
D is incorrect because there are three factors in that multiplication term: 5, <em>y</em>, and <em>z.</em>
A logarithmic function without a subscript means that it must be log base 10.

When learning about logarithms, a textbook/teacher provides their students with the following general equations


Hopefully you are familiar with this. Using the equations that I just showed, we can change the equation
to 
This would make answer choice C correct.
Answer:
72yd2
Step-by-step explanation:
making figure into 2
1st figure
= 6×5
= 30yd^2
2nd figure
= 14×3
= 42yd^2
Area of the full figure
= (30+42)yd^2
= 72yd^2
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