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zaharov [31]
2 years ago
13

There are 7 times as many females as

Mathematics
1 answer:
Bas_tet [7]2 years ago
8 0

Answer:

1/7

Step-by-step explanation:

men = x

female = 7x

x+7x=8x

female fractions = 7/8

male fractions =1/7

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How do you solve this equation log(3x+1)=5
Len [333]

log_{10} 3x+1=5

3x+1=10^5

3x+1=100000

3x=99999

x=333333


Just remember that in the form of log_ab=x, you get a^x=b.


7 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! THIS LINEAR EQUATIONS!!!
melomori [17]
The answer is C,
120x + 60y \geqslant 600
We use the 'more than or equal sign' as the consultant needs to make at least $600 - so exactly $600 or more than $600
4 0
3 years ago
The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from
melomori [17]

Answer:

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=p

\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

8 0
3 years ago
The box and whisker plots below show two classes' semester grades. Write a paragraph comparing the two sets of
oksano4ka [1.4K]

The paragraph to show the comparision between two classes semester grades on the basis of the terms

  • extremes
  • quartiles
  • medians
  • ranges

is given below:

<h3>What is Box and Whisker plots?</h3>

A box and whisker plot is defined as a graphical method of displaying variation in a set of data.

From the first figure, write all the values where dark point is drawn

53, 62, 80, 86, 89  

  • The lower extreme is the smallest value, which is 53.

        The upper extreme is the highest value, which is 89.

  • The median will be the middle of data , which is 80

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

        The upper quartile is 86 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =89-53

       =36

From the second figure, write all the values where dark point is drawn

56, 62, 74, 89, 96

  • The lower extreme is the smallest value, which is 56.

        The upper extreme is the highest value, which is 96.

  • The median will be the middle of data , which is 74.

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

       The upper quartile is 89 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =96-62

       =34

From the above discussion,  

  • The First class have less upper extreme value than the second class.
  • The First class have less lower extreme value than the second class.
  • The First class have greater median than the second class.
  • The First class have less upper quartile than the second class.
  • The First and second class have equal lower quartile.
  • The First class have greater range than the second class.

The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.

learn more about box and whisper plot here:

brainly.com/question/11859288

#SPJ1

6 0
1 year ago
A pecan pie is being served for dessert. One piece of pie has an arc length of 7.85 in. It has been cut into 8 equal pieces. Wha
grin007 [14]

Answer:

The radius of the pie is 6.17 in.

Step-by-step explanation:

The formula for arc length as a function of radius is

s = r·Ф, where Ф is the central angle in radians.

Here we know that the arc length is 7.85 in.  Assuming that the whole pie has been cut into 8 equal pieces, the central angle of one such piece is

2π / 8, or π /4 (radians).

thus, s = r·Ф, solved for r, is r = s/Ф

and in this instance r = (7.85 in)/(π/4).  Evaluating this, we get:

                                 r = 6.17 in

The radius of the pie is 6.17 in.

8 0
3 years ago
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