We are given the equation:
..........(1)
Now we have to write it in quadratic form using substitution.
The general form of quadratic equation is given by:
So let us say
.......(2)
Plugging the value of (x-5)² from equation (2) in (1),
Answer : Option B.
Answer:
a. 3942 kWh
b. $473.04
c. 1314 kWh
d. $157.68
Step-by-step explanation:
<h3>a. </h3>
There are 1000 W in 1 kW, so 450 W = 0.450 kW. The energy used per day is ...
(0.45 kW)(24 h) = 10.8 kWh . . . . energy per day
Then in a 365-day year, the energy used is
(365 da/yr)(10.8 kWh/da) = 3942 kWh/yr
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<h3>b.</h3>
At the rate of $0.12/kWh, the cost of running the pump is ...
($0.12/kWh)(3942 kWh/yr) = $473.04/yr
__
<h3>c.</h3>
Switching the pump off for 1/3 of the time will save 1/3 of the energy found in part (a):
1/3(3942 kWh) = 1314 kWh . . . . energy saved by switching off the pump
__
<h3>d.</h3>
The savings will be 1/3 of the cost of running the pump full time:
1/3($473.04/yr) = $157.68/yr
Answer:
9-7x+9+25+6x-4=47-x
Step-by-step explanation:
Answer:
8 dolls
Step-by-step explanation:
METHOD 1:
Step 1: Convert 25% into decimal (0.25)
Step 2: Multiply by 32 (32 × 0.25 = 8)
METHOD 2:
25% of a number will be one-fourth of that number. Divide 32 by 4 to get 8 (or multiply 32 by 1/4).
