Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,
.....(1)
For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.
Answer:
The answer is “C” (Shifts left 3 units)
Step-by-step explanation:
To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.
The solution is
.
Solution:
Given inequality:

Divide by 7 on both sides.


The solution is
.
The image of the graph is attached below.
Answer:
No :)
Step-by-step explanation:
the graph does not make a straight line. :)