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3241004551 [841]
4 years ago
10

An amusement park manager determined that about 2/3 of all customers would wait in long lines to ride the new roller coaster. Wh

ich simulation could NOT be used to answer questions about whether a customer would wait?

Mathematics
2 answers:
Deffense [45]4 years ago
5 0

Answer:

The coin flipping one

Step-by-step explanation:

Because it only as 2 possible outcomes and the other ones have more than one I just picked that one.

egoroff_w [7]4 years ago
3 0

Answer:

The correct answer is the first one  I got it right

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A store is advertising that it offers a 14% discount had on everything purchased at the store. When Aiza (آئزہ) had paid $670.80
White raven [17]

Answer:

780

Step-by-step explanation:

6 0
3 years ago
(7y – 20)<br> (5х – 38)<br> (3х – 4)<br> -<br> m
egoroff_w [7]

Answer:

um

Step-by-step explanation:

8 0
2 years ago
I need the answer for part b​
Softa [21]

Answer:

4/4

Step-by-step explanation:

1/4 plus 1/4 plus 2/4 is 4/4

4 0
2 years ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

6 0
4 years ago
The product of two numbers is 2400 iftheir LCM is 120 find their LCM.... BY STEPS!!..... ​
aliina [53]

Answer:

60 and 40 or 120 and 20

Step-by-step explanation:

60 x 2=120

40 x 3=120

60 x 40=2400

120 x 1=120

20 x 6=120

120 x 20=2400

You can try a few others, but no others have an lcm of 120

4 0
4 years ago
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