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2 years ago

Which was the first university of the world

Mathematics

1 answer:

lianna [129]2 years ago

7 0

Answer:

Sankore University

Step-by-step explanation:

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Answer question 4 pls for math

brilliants [131]

Answer:

Rule: y = 2x

m = 2

b = 0

Step-by-step explanation:

(17, 34) and (22, 44)

<u>Slope:</u>

m=(y2-y1)/(x2-x1)

m=(44-34)/(22-17)

m= (10)/5

m = 2

<u>Slope-intercept:</u>

y - y1 = m(x - x1)

y - 34 = 2(x - 17)

y - 34 = 2x - 34

y = 2x

y = mx + b

y = 2x

b = 0

3 0

3 years ago

If x^(2) = 64 and y^(2)= 121 what is the value of x-y?

GalinKa [24]

Step-by-step explanation:

<em>the value of x is 8</em>

8^(2) = 64

the value of y is 11

11^(2) = 121

x - y

= 8 - 11

= -3

<h3>#CMIIW</h3>

3 0

2 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

On another Ferris wheel, a car will travel 100.48m once around the wheel. What is the height from the top car to the bottom car?

sasho [114]

Answer:

the hieght will be 58.10m

Step-by-step explanation:

5 0

3 years ago

ABCD is a parallelogram. Segment AC = 4x + 10. Find the value of x and y.

valkas [14]

Answer:

The values of x and y in the diagonals of the parallelogram are x=0 and y=5

Step-by-step explanation:

Given that ABCD is a parallelogram

And segment AC=4x+10

From the figure we have the diagonals AC=3x+y and BD=2x+y

By the property of parallelogram the diagonals are congruent

∴ we can equate the diagonals AC=BD

That is 3x+y=2x+y

3x+y-(2x+y)=2x+y-(2x+y)

3x+y-2x-y=2x+y-2x-y

x+0=0 ( by adding the like terms )

∴ x=0

Given that segment AC=4x+10

Substitute x=0 we have AC=4(0)+10

=0+10

=10

∴ AC=10

Now (3x+y)+(2x+y)=10

5x+2y=10

Substitute x=0, 5(0)+2y=10

2y=10

$y=\frac{10}{2}$

∴ y=5

∴ the values of x and y are x=0 and y=5

5 0

3 years ago

Which was the first university of the world ​

Which was the first university of the world