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FinnZ [79.3K]
4 years ago
9

Find the solutions to the given system of equations

Mathematics
2 answers:
marin [14]4 years ago
8 0
\bf \begin{cases}
x^2+y^2=15\\
y^2=15-x^2\\
y=\sqrt{15-x^2}\\
-------\\
y=-x-6
\end{cases}\qquad \qquad \sqrt{15-x^2}=-x-6
\\\\\\
\textit{again, squaring both sides}\implies 15-x^2=(-x-6)^2\\\\
-------------------------------\\\\
15-x^2=x^2+12x+36\implies 0=2x^2+12x+21
\\\\\\
\textit{now, let's check the discriminant of it}
\qquad 
\begin{array}{llccll}
0=&{{ 2}}x^2&{{ +12}}x&{{ +21}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}

\bf discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}
\\\\\\
12^2-4(2)(21)\implies 144-168\implies -24

notice, the discriminant is negative.


on the second system of equations there, check for any typos, there's a solution however, is none of those.
ladessa [460]4 years ago
6 0
Your closeest awnsers D
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