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3 years ago

What is 8v+w+7−8v+2w

Mathematics

1 answer:

Bingel [31]3 years ago

3 0

Answer:

3w+7

Step-by-step explanation:

Let's simplify step-by-step.

8v+w+7−8v+2w

=8v+w+7+−8v+2w

Combine Like Terms:

=8v+w+7+−8v+2w

=(8v+−8v)+(w+2w)+(7)

=3w+7

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A square pool is surrounded by a paved area that is 2 metres wide. If the area of the paving is 72m2, what is the length of the

likoan [24]

The length of the square pool is 8. 49cm

<h3>How to determine the area</h3>

Note that the formula for finding the area of a square is given as;

Area = length^2

We have

Area = 72 m²

Substitute into the formula

I^2 = 72

Find the square root of both sides

I= √72

I = 8. 49cm

The length of the square pool given as I is 8. 49cm

Thus, the length of the square pool is 8. 49cm

Learn more about area of a square here:

brainly.com/question/486778

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2 years ago

What is 2,034,627 rounded to the nearest ten thousand

MatroZZZ [7]

Answer:

rounded to the nearest ten thousand

2,034,627

2,030,000

6 0

3 years ago

Sinplify this expression -3(10x+4y)+6(6x-2y)

ad-work [718]

Answer:

6x-24y

Step-by-step explanation:

Step 1: -30x-12y+36x-12y

Distribute-3 to 10x and 4y

Then distribute 6 to 6x and -2y

Step 2: 6x-24y

After that add up like terms

3 0

4 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

4 0

4 years ago

What is the equation of the line that passes through the point (6,3) has a slope of -1/3

DerKrebs [107]

Answer:

y = -1/3x + 5

Step-by-step explanation:

y = mx + b

so y = 3, x = 6, m = -1/3

then 3 = (-1/3)6 + b

3 = -2 + b

b = 5

so y = -1/3x + 5

5 0

2 years ago