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lozanna [386]
3 years ago
10

Suppose we take two different random samples from the same population of test scores. The population mean and standard deviation

are unknown. The first sample has 25 data values. The second sample has 64 data values. Then we construct a 95% confidence interval for each sample to estimate the population mean. Which confidence interval would you expect to have greater precision (smaller width) for estimating the population mean? (i) I expect the confidence interval based on the sample of 64 data values to be more precise. (ii) I expect both confidence intervals to have the same precision. (iii) I expect the confidence interval based on the sample of 25 data values to be more precise.
Mathematics
1 answer:
denis23 [38]3 years ago
6 0

Answer:

The correct option is (i) I expect the confidence interval based on the sample of 64 data values to be more precise.

Step-by-step explanation:

Consider the provided information.

The sample size is inversely proportional to the standard error of the sample mean decreases. \sigma_M=\frac{\sigma}{N}

As the size increase the standard error of the sample mean decreases.

Hence, for greater precision select the confidence interval based on the greater sample of data.

Therefore, we expect the confidence interval based on the sample of 64 data values to be more precise.

The correct option is (i) I expect the confidence interval based on the sample of 64 data values to be more precise.

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Three children each had the same amount of money in their savings account. One of the children withdrew a quarter of her money a
malfutka [58]
The total money with them was $100 in their accounts
3 0
4 years ago
A new DVD is available for sale in a store one week after its release. The cumulative revenue,
ratelena [41]

Answer:

f(2) = $180.22

f'(2) = $130.00/week

f'(2)/f(2) = 72.13%

Two weeks after the DVD was released,  the revenue from sales is $180.22 and is increasing at a rate of $130 per week,  or 72.13% per week.

Step-by-step explanation:

The revenue from sales, in dollars, as a function of time, in weeks, is given by:

f(t)=260ln(t)

After two weeks (t=2), the revenue from sales is:

f(2)=260ln(2)\\f(2) = \$180.22

The rate of change, which is given by the derivate of the revenue function, at t = 2 weeks is:

f'(t)=\frac{d}{dt} 260ln(t)\\f'(t) = \frac{260}{t}\\f'(2) = \frac{260}{2}=\$130.00/week

The relative rate of change is:

\frac{f'(2)}{f(2)}=\frac{130}{180.22}=0.7213=72.13\%

Therefore, Two weeks after the DVD was released,  the revenue from sales is $180.22 and is increasing at a rate of $130 per week,  or 72.13% per week.

5 0
4 years ago
What is 8-8 to the power of -1 ?
Aleksandr-060686 [28]
8-8^-1
=8-1/8  <<< 8*8=64 then 64-1=63
=63/8
in decimal(7.875)


4 0
3 years ago
The area A (in square feet) of the rectangular shed is given by
a_sh-v [17]

This question is incomplete.

Complete Question

The area A (in square feet) of the rectangular shed is given by 6x³+7x²+11x+21.And one side of the rectangular is 2x+3. Use polynomial long division to find an expression for the length (in feet) of the shed.

Answer:

3x² - x +7

Step-by-step explanation:

Using the long division method:

We have :

Divisor : 6x³+7x²+11x+21

Dividend : 2x+3

Quotient : the length (in feet) of the shed = ???

Hence, we solve below

6x³+7x²+11x+21 ÷ 2x + 3

3x² -x + 7

______________________

2x+3 l 6x³+7x²+11x+21

6x³+9x²

__________

-2x²+11x

-2x²-3x

__________

14x+21

14x+21

_______

0

Therefore, an expression for the length (in feet) of the shed is 3x² - x +7

8 0
3 years ago
Solve the inequality:<br><br> 444 + 555y &lt; 333
zhannawk [14.2K]

The solution is y < -1/5

In order to find the answer to this problem, follow the order of operations for solving equations/inequalities.

444 + 555y < 333 -----> Subtract 444 from both sides

555y < -111 -----> Divide both sides by 555

y < -1/5

5 0
3 years ago
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