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lozanna [386]
3 years ago
10

Suppose we take two different random samples from the same population of test scores. The population mean and standard deviation

are unknown. The first sample has 25 data values. The second sample has 64 data values. Then we construct a 95% confidence interval for each sample to estimate the population mean. Which confidence interval would you expect to have greater precision (smaller width) for estimating the population mean? (i) I expect the confidence interval based on the sample of 64 data values to be more precise. (ii) I expect both confidence intervals to have the same precision. (iii) I expect the confidence interval based on the sample of 25 data values to be more precise.
Mathematics
1 answer:
denis23 [38]3 years ago
6 0

Answer:

The correct option is (i) I expect the confidence interval based on the sample of 64 data values to be more precise.

Step-by-step explanation:

Consider the provided information.

The sample size is inversely proportional to the standard error of the sample mean decreases. \sigma_M=\frac{\sigma}{N}

As the size increase the standard error of the sample mean decreases.

Hence, for greater precision select the confidence interval based on the greater sample of data.

Therefore, we expect the confidence interval based on the sample of 64 data values to be more precise.

The correct option is (i) I expect the confidence interval based on the sample of 64 data values to be more precise.

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Answer:

$112.08 every year.

Step-by-step explanation:

Let's suppose a game in which we bet a certain amount of money ''A'' to a certain result and the probability of that result is ''p''. If the prize that we get is ''P'' therefore the expected value of gain is  :

E=p(P-A)+(1-p)(-A)=pP-A

Now,let's suppose that the female is ''betting on her death'' ⇒

P(she survives) = 0.999592

P(she doesn't survive) = 1 - 0.999592=4.08(10^{-4})

E(25-year old female) = 4.08(10^{-4}).(240000)-210=-112.08

The negative sign of E is important.It means that every year the 25-year old female will lose $112.08.

Therefore, the expected value of this policy to the insurance company is $112.08 every year.

5 0
3 years ago
What is the measure of x?
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The measure of x is 24 degrees
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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

6 0
2 years ago
Tyrell's SAT math score was in the 64th percentile. If all SAT math scores are normally distributed with a mean of 500 and a sta
jarptica [38.1K]

Answer:

P(x < 535.8) = 0.64

P_{64} = 535.8

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.64

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Calculation the value from standard normal z table, we have,  p(z

\displaystyle\frac{x - 500}{100} = 0.358\\x = 535.8

P(x < 535.8) = 0.64

P_{64} = 535.8

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3 years ago
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