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Helga [31]
3 years ago
8

Brynn and Denise launch their rockets at the same time. The height of Brynn’s rocket, in meters, is given by the function f(x)=−

4.9x^2+75x , where x is the number of seconds after the launch.
The height of Denise’s rocket, in meters, is given by the function g(x)=−4.9x^2+50x+38 , where x is the number of seconds after the launch.

There is a moment when the rockets are at the same height.



What is this height rounded to the nearest tenth of a meter?
Mathematics
1 answer:
pishuonlain [190]3 years ago
3 0
-4.9x²+75x=-4.9x+50x+38
75x=50x+38
25x=38
x=1.52
1.52 minutes after launching, the height is: -4.9(1.52)²+75(1.52)=102.67904≈102.7 meters
Double check: -4.9(1.52)²+50(1.52)+38=102.67904≈102.7. Yes.
so the height is 102.7 meter.
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