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Y_Kistochka [10]
4 years ago
10

Simplify the rational expression. State any excluded values. x^2-36/6-x

Mathematics
2 answers:
ella [17]4 years ago
4 0

Answer:

-x - 6; where x does not equal 6 is correct.

Step-by-step explanation:

kherson [118]4 years ago
3 0
Before you start notice that division by zero is undefined, thus the denominator cannot equal zero which means that:

6-x!=0

6!=x

So x cannot equal 6...the proceed to simplifying...

(x^2-36)/(6-x)  the numerator is a "difference of squares" having the form:

(a^2-b^2) which always factors to (a+b)(a-b) so what you actually have is:

((x+6)(x-6))/(6-x)  if you factor out -1 from the second factor in the numerator you have:

(-1(x+6)(6-x))/(6-x)  now you can see that the (6-x)s cancel out leaving:

-1(x+6) which is equal to

-x-6, just remember that x cannot equal 6 as we saw in the beginning...
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Help!!!!!!!!!!!!!!!!​
kaheart [24]

Answer:

\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)

Step-by-step explanation:

First, simplify each term:

\sin\left(\dfrac{\pi}{2}+\alpha\right)=\cos \alpha\\ \\\cos \left(\dfrac{\pi}{2}+\alpha\right)=-\sin \alpha\\ \\\cos \left(\alpha-\dfrac{3\pi}{2}\right)=-\sin \alpha\\ \\\sin \left(\dfrac{3\pi}{2}+\alpha\right)=-\cos \alpha

Then given expression is equivalent to

\cos ^3\alpha+(-\sin \alpha)^3-(-\sin \alpha)+(-\cos \alpha)\\ \\=\cos ^3\alpha-\sin^3 \alpha+\sin \alpha-\cos \alpha\\ \\=(\cos\alpha-\sin\alpha)(\cos^2\alpha+\cos\alpha\sin\alpha+\sin^2\alpha)-(\cos\alpha-\sin\alpha)\\ \\=(\cos\alpha-\sin\alpha)(1+\cos\alpha\sin\alpha-1)\ \ [\cos^2\alpha+\sin^2\alpha=1]\\ \\=\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)

6 0
3 years ago
find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next
zalisa [80]

Answer:

The number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

Step-by-step explanation:

We need to find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​.

There are 9 letters in the word WONDERFUL

There is a condition that letter R is always next to E.

So, We have two letters fixed WONDFUL (ER)

We will apply Permutations to find ways of arrangements.

The 7 letters (WONDFUL) can be arranged in ways : ⁷P₇ = 7! = 5040 ways

The 2 letters (ER) can be arranged in ways: ²P₂ =2! = 2 ways

The number of ways 'WONDERFUL' can be arranged is: (5040*2) = 10,080 ways

So, the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

8 0
3 years ago
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Hitman42 [59]
I honestly have no clue i just need to answer a question do i can ask my question that i needed help with,
8 0
3 years ago
A regular hexagon has an apothem of 14.7 inches and a perimeter of 101.8 inches. what is the area of the hexagon? square inches
WINSTONCH [101]

Answer:

748.23 in^2.

Step-by-step explanation:

Area = 1/2 * apothem * perimeter

        = 1/2 * 14.7 * 101.8

        =  748.23 in^2.

3 0
2 years ago
Read 2 more answers
Find the value of each variable and the measure of each angle​
Misha Larkins [42]

Answer:

Left angle = 60°

Top angle = 120°

Right angle = 60°

Step-by-step explanation:

Use what you know about angle relationships to set up equations you can solve for each variable.

The top top angle, for example, added to one of the other angles must equal 180° because they are supplementary.

You have two variables, so you need at least two equations (I made three but only used two).

The work is in my attachment, comment of you have questions.

8 0
3 years ago
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