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bagirrra123 [75]
4 years ago
12

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). A six-sided die

of unknown bias is rolled 20 times, and the number 3 comes up 6 times. In the next three rounds (the die is rolled 20 times in each round), the number 3 comes up 6 times, 5 times, and 7 times. The experimental probability of rolling a 3 is %, which is approximately % more than its theoretical probability. (Round off your answers to the nearest integer.)
Mathematics
1 answer:
Mice21 [21]4 years ago
7 0

Answer:

The experimental probability of getting a 3 on a die is 30% which is approximately 13% more than its theoretical probability (17%).

Step-by-step explanation:

Theoretical probability of number 3 on a die:

Total no. of possibilities = 6

Probability of getting a 3 on a die each time it is rolled = 1/6

= 0.16667

= 17%

Experimental probability of number 3 on a die:

Total no. of rounds = 4

Rolls each round = 20

no. of 3s in round 1 = 6

no. of 3s in round 2 = 6

no. of 3s in round 3 = 5

no. of 3s in round 4 = 7

Total rolls = 20*4 = 80

no. of times 3 comes up = 6+6+5+7 = 24

Experimental probability of getting a 3 on a die

each time it is rolled = no. of 3s/total rolls

= 24/80

= 0.3

= 30%

Difference = 30% - 17% = 13%

Experimental probability of getting a 3 on a die is 30% which is approximately 13% more than its theoretical probability (17%).

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-2 8/9 as a decimal and how to get it
slavikrds [6]

Answer: -2.88889

Step-by-step explanation:

calculate the approimate value

8 0
4 years ago
In an isosceles triangle two sides are equal. The third side is two less than twice the length of the two equal sides. The perim
pogonyaev

Answer:

The equal sides' length = 10

Third side length = 18

Step-by-step explanation:

Let the two equal sides' length be "x"

Let the third side length be "y"

Third side (y) is 2 LESS THAN TWICE the equal side, so we can write:

y = 2x - 2

The perimeter is 38. The perimeters is the sum of all three sides. So we can write:

x + x + y = 38

Replacing y with 2nd equation, we have:

x + x + (2x - 2) = 38

Now, we can solve this for x first:

x + x + (2x - 2) = 38\\x+x+2x-2=38\\4x=38+2\\4x=40\\x=10

Now, y is:

y = 2x - 2

y = 2(10) - 2

y = 20 - 2

y = 18

The equal sides' length = 10

Third side length = 18

3 0
3 years ago
How do you find the tenth term in this sequence
slava [35]

Answer:

should be none of the about because each time you multiple by 1/2, i got 1/64 for the 10th

Step-by-step explanation:

7 0
3 years ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
Question 1 (1 point) Point M is the midpoint of AB. The coordinates of point A are (-6, 3) and the coordinates of M are (-1, 1).
konstantin123 [22]

Answer:

The answer to your question is:  (4, -1)

Step-by-step explanation:

M = midpoint   (-1, 1)

A = (-6, 3)

B = (x, y)

xm = \frac{x1 + x }{2}

x = 2xm - x1

x = 2(-1) + 6

x = -2 + 6

x = 4

ym = \frac{y1 + y }{2}

y = 2ym - y1

y = 2(1) - 3

y = 2 - 3

y = -1

4 0
4 years ago
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