(
3
x
3
2
y
3
x
2
y
−
1
2
)
−
2
(
3
x
3
2
y
3
x
2
y
-
1
2
)
-
2
Move
x
3
2
x
3
2
to the denominator using the negative exponent rule
b
n
=
1
b
−
n
b
n
=
1
b
-
n
.
⎛
⎝
3
y
3
x
2
y
−
1
2
x
−
3
2
⎞
⎠
−
2
(
3
y
3
x
2
y
-
1
2
x
-
3
2
)
-
2
Multiply
x
2
x
2
by
x
−
3
2
x
-
3
2
by adding the exponents.
Tap for more steps...
(
3
y
3
x
1
2
y
−
1
2
)
−
2
(
3
y
3
x
1
2
y
-
1
2
)
-
2
Move
y
−
1
2
y
-
1
2
to the numerator using the negative exponent rule
1
b
−
n
=
b
n
1
b
-
n
=
b
n
.
(
3
y
3
y
1
2
x
1
2
)
−
2
(
3
y
3
y
1
2
x
1
2
)
-
2
Multiply
y
3
y
3
by
y
1
2
y
1
2
by adding the exponents.
Tap for more steps...
⎛
⎝
3
y
7
2
x
1
2
⎞
⎠
−
2
(
3
y
7
2
x
1
2
)
-
2
Change the sign of the exponent by rewriting the base as its reciprocal.
⎛
⎝
x
1
2
3
y
7
2
⎞
⎠
2
(
x
1
2
3
y
7
2
)
2
Use the power rule
(
a
b
)
n
=
a
n
b
n
(
a
b
)
n
=
a
n
b
n
to distribute the exponent.
Tap for more steps...
(
x
1
2
)
2
3
2
(
y
7
2
)
2
(
x
1
2
)
2
3
2
(
y
7
2
)
2
Simplify the numerator.
Tap for more steps...
x
3
2
(
y
7
2
)
2
x
3
2
(
y
7
2
)
2
Simplify the denominator.
Tap for more steps...
x
9
y
7
The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range. So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.
|18.62-18.25|>.36
.37>.36
18.62 is not in range.
Answer:
2:12
Step-by-step explanation:
6 and 4 = 10
5 and 5 = 10
Answer:
D. 32
Step-by-step explanation:
116 + 2b = 180
2b = 64
b = 32