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3 years ago

Does anyone understand and can help me asap?

Mathematics

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

Circumference of circle = 2πr =dπ

Area of circle =πr²

1) Circle1 d =4 in, r =2 in

Circumference of circle1 =4π in

Area of circle1 = 2²π =4π in²

2) Circle2: d =3 in, r =1.5 in

Circumference of circle2 =3π in

Area of circle2 = 1.5²π =2.25π in²

3) Circle3: r =1 in, d =2 in

Circumference of circle3 =2π in

Area of circle3 = 1²π =π in²

4) Circle4: r =2 1/2 in = 2.5 in, d =5 in

Circumference of circle4 =5π in

Area of circle4 = 2.5²π = 6.25π in²

5) 2/3 of the Area of circle1 = (2/3)*4π in²= (8/3)π in²

6) 1/2 of the Area of circle2 = (1/2)*2.25π in² = (1/2)*(9/4)π in² = (9/8)π in²

7) 1/4 of the Area of circle3 = (1/4)π in²

8) 1/3 of the Area of circle4 = (1/3)* 6.25π in² =(1/3)*(25/4)π in² = (25/12)π in²

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3 years ago

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2 years ago

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DanielleElmas [232]

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Step-by-step explanation:

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2 years ago

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ehidna [41]

Answer:

25.047 or roughly 25.

Step-by-step explanation:

I solved it wrong the first time then i double check with wolframalpha and got the correct number.

We know that the area of the tile is 18 $\sqrt{3}$ and it makes a triangle, we also know the base and height. In this case the base is 2 $\sqrt{3}^{x/12}$ and the height is also given which is $\sqrt{3}^{\frac{x}{6} }$ .

Area of triangle = $\frac{bh}{2}$ ,

substituting we will end up with 18 $\sqrt{3}$ =( 2 $\sqrt{3}^{x/12}$ * $\sqrt{3}^{\frac{x}{6} }$ ) / 2

Here is the tricky part $\sqrt{x} = x^{\frac{1}{2} }$ , i totally forgot about that lol.

Simplifying: we will get 18 $\sqrt{3}$ = $3^{\frac{x}{8} }$

Now, in order to find the x, we will need to take the log of both sides.

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Solving for x we end up getting:

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To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

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3 years ago

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3 years ago