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Sergeu [11.5K]
4 years ago
12

What percent of 37 is 111?

Mathematics
1 answer:
exis [7]4 years ago
4 0
111 is 300% of 37. This is how I do it. 37x=111 x=111/37 x=3 move the decimal point right 2 places to get the percentage 300% ANSWER 300%
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Emilio has 5 bags of birdseed .Each bag has about 28 ounces of birdseed . If he divides the birdseed equally into 3 containers ,
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total ounces of birdseed = 5*28=140

number of birdseed of a container = 140/3 = 46.6666 ounces =140/3 ounces

he will put 140/3 ounces in each container


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Y = x – 6 x = –4 what is the solution to the system of equations? (–8, –4) (–4, –8) (–4, 4) (4, –4
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(- 4, - 10 )

Step-by-step explanation:

Given the 2 equations

y = x - 6 → (1)

x = - 4 → (2)

Substitute x = - 4 into (1) for corresponding value of y

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3 0
4 years ago
In October of 2012, Apple introduced a much smaller variant of the Apple iPad, known at the iPad Mini. Weighing less than 11 oun
sveticcg [70]

Answer:

a. f_X(x) = \dfrac{1}{3.5}8.5

b. the probability that the battery life for an iPad Mini will be 10 hours or less is 0.4286 which is about 42.86%

c.  the probability that the battery life for an iPad Mini will be at least 11 hours is 0.2857 which is about 28.57 %

d. the probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours is 0.5714 which is about 57.14%

e.  86 should have a battery life of at least 9 hours

Step-by-step explanation:

From the given information;

Let  X represent the continuous random variable with uniform distribution U (A, B) . Therefore the probability  density function can now be determined as :

f_X(x) = \dfrac{1}{B-A}A

where A and B  are the two parameters of the uniform distribution

From the question;

Assume that battery life of the iPad Mini is uniformly distributed between 8.5 and 12 hours

So; Let A = 8,5 and B = 12

Therefore; the mathematical expression for the probability density function of battery life is :

f_X(x) = \dfrac{1}{12-8.5}8.5

f_X(x) = \dfrac{1}{3.5}8.5

b. What is the probability that the battery life for an iPad Mini will be 10 hours or less (to 4 decimals)?

The  probability that the battery life for an iPad Mini will be 10 hours or less can be calculated as:

F(x) = P(X ≤x)

F(x) = \dfrac{x-A}{B-A}

F(10) = \dfrac{10-8.5}{12-8.5}

F(10) = 0.4286

the probability that the battery life for an iPad Mini will be 10 hours or less is 0.4286 which is about 42.86%

c. What is the probability that the battery life for an iPad Mini will be at least 11 hours (to 4 decimals)?

The battery life for an iPad Mini will be at least 11 hours is calculated as follows:

P(X\geq11) = \int\limits^{12}_{11} {\dfrac{1}{3.5}} \, dx

P(X\geq11) =  {\dfrac{1}{3.5}} (x)^{12}_{11}

P(X\geq11) =  {\dfrac{1}{3.5}} (12-11)

P(X\geq11) =  {\dfrac{1}{3.5}} (1)

P(X\geq11) = 0.2857

the probability that the battery life for an iPad Mini will be at least 11 hours is 0.2857 which is about 28.57 %

d. What is the probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours (to 4 decimals)?

P(9.5 \leq X\leq11.5) =\int\limits^{11.5}_{9.5} {\dfrac{1}{3.5}} \, dx

P(9.5 \leq X\leq11.5) ={\dfrac{1}{3.5}} \, (x)^{11.5}_{9.5}

P(9.5 \leq X\leq11.5) ={\dfrac{1}{3.5}} (11.5-9.5)

P(9.5 \leq X\leq11.5) ={\dfrac{1}{3.5}} (2)

P(9.5 \leq X\leq11.5) =0.2857* (2)

P(9.5 \leq X\leq11.5) =0.5714

Hence; the probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours is 0.5714 which is about 57.14%

e. In a shipment of 100 iPad Minis, how many should have a battery life of at least 9 hours (to nearest whole value)?

The probability that battery life of at least 9 hours is calculated as:

P(X \geq 9) = \int\limits^{12}_{9} {\dfrac{1}{3.5}} \, dx

P(X \geq 9) =  {\dfrac{1}{3.5}}(x)^{12}_{9}

P(X \geq 9) =  {\dfrac{1}{3.5}}(12-9)

P(X \geq 9) =  {\dfrac{1}{3.5}}(3)

P(X \geq 9) =  0.2857*}(3)

P(X \geq 9) =  0.8571

NOW; The Number of iPad  that should have a battery life of at least 9 hours is calculated as:

n = 100(0.8571)

n = 85.71

n ≅ 86

Thus , 86 should have a battery life of at least 9 hours

3 0
3 years ago
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