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pychu [463]
4 years ago
12

A social media website currently has 1000 members. The number of people that join the website triples every month. After how man

y months will the website have more than 1 million members? Talk the beginning as month 0
Mathematics
2 answers:
Harlamova29_29 [7]4 years ago
6 0
At 7 months it would b3 2,187,000 hope this helps
algol134 years ago
6 0
Members = 1,000*3^t where t = months
So after
0 months  1,000 members
1 month    3,000 members
2 months  9,000 members

If we are to solve that for a million:
Members/1,000 = 3^t
1,000,000/1,000 = 3^t
1,000 = 3^t 
Taking logs of both sides
log 1,000 = time*log(3)
3 = time * <span> <span> <span> 0.4771212547 </span> </span> </span>
time = 3/ <span> <span> <span> 0.4771212547 </span> </span> </span>
time = <span> <span> <span> 6.2877098229 </span> </span> </span> months
Okay about 6.29 months

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Step-by-step explanation:

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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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3 years ago
BRAINLIEST FOR CORRECT ANSWER!!!<br> Please Help!
vlada-n [284]

Answer:

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6 0
3 years ago
Read 2 more answers
PLEASE HELP!! Algebra 2 Review !!
Kamila [148]

Answer:

\frac{28-3i}{26}

Step-by-step explanation:

For #2, remember that i=\sqrt{-1}, so i^{2}=-1 Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)=a^2-b^2. Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number a+bi, where a and b are any numbers, the conjugate is always a-bi. Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:

\frac{5+6i}{4+6i}=\frac{(5+6i)(4-6i)}{(4+6i)(4-6i)}=\frac{20+24i-30i+36}{16+36}=\frac{56-6i}{52}=\frac{2(28-3i)}{2(26)}=\frac{28-3i}{26}

Our answer is (28-3i)/(26)!

6 0
3 years ago
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