I don’t know................
Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
3(4x + 6) + 7x
12x + 18 + 7x
19x + 18 <==
Answer:
Step-by-step explanation:
The 20th of February for seven nights:
Mr. Jones: 714
Mrs. Jones: 714
Child 1: 95% of 714 = 678.30
Child 2: 95% of 714 = 678.30
Total Price: 2784.60
The 10th of April for fourteen nights:
Mr. Jones: 802
Mrs. Jones: 802
Child 1: 85% of 802 = 681.70
Child 2: 85% of 802 = 681.70
Total Price: 2967.40
The 10th of April for fourteen nights is 182.80 pounds greater than the 20th of February for seven nights.
