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AveGali [126]
3 years ago
9

Divide. Write the quotient in lowest terms. 3/5. Devide by 2 1/2 how much ????

Mathematics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

The answer is .24, or 6/24

Step-by-step explanation:

Its easiest to convert the 2 answers into decimals and then solve.

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If -3 1/4 is subtracted from 1 1/3. What will be the result?
Alenkinab [10]

1_1/3 = 4/3

-3_1/4 = -13/4

(4/3) - (-13/4)

(4/3) + (13/4)

We can see that (4/3) + (13/4) leads to a positive answer.

Answer: choice D

4 0
3 years ago
Which of the lines graphed has a slope of -2 and a y intercept of 3?
Flura [38]
It's out of D or A I can't really see 
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2 years ago
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

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3 years ago
Kimmy bought a 5 kilogram can of peanuts for $4.50. What is the unit price?
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The Spotlight on Teaching and Learning at the beginning of this chapter discusses the emphasis in the Common Core State Standard
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