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3 years ago

Please help tysm guys <3 make sure to put what question ur answering if ur doing one tysm!

Mathematics

2 answers:

DiKsa [7]3 years ago

7 0

Question 12)
- No, because corresponding sides are not proportional.

Question 13)
- Yes, because corresponding sides are proportional.

frozen [14]3 years ago

3 0

Answer:

(Question 12) The answer would be B, they are not proportional.

Step-by-step explanation:

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4 years ago

Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3

LekaFEV [45]

Answer:

$(a)\ \sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128} = 8 \sqrt{2}$

Step-by-step explanation:

Required

Simplify

$(a)\ \sqrt{20}$

Express 20 as 4 * 5

$\sqrt{20}=\sqrt{4 * 5}$

Split

$\sqrt{20}=\sqrt{4} * \sqrt{5}$

This gives:

$\sqrt{20}=2 * \sqrt{5}$

$\sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300$

Express as 100 * 3

$\sqrt{300} = \sqrt{100} * \sqrt{3}$

This gives:

$\sqrt{300} = 10 * \sqrt{3}$

$\sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128}$

Express as 64 * 2

$\sqrt{128} = \sqrt{64*2}$

Split

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

Questions 4 and 5 are not clear

Follow the steps in 1 - 3 to solve 4 and 5

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3 years ago