Part A:
The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

Part B:
</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and
standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:
</span>
Answer:
$2.92
Step-by-step explanation:
35/12 = 2.91666666667
1 rose = 2.91666666667 = $2.92
Answer: function 1
Rate of change of function 1:
Following the format of y=mx+c, the rate of change should be m, so, the rate of change for function 1 = 4
To find the gradient (rate of change):
The two points the line passes through are (x1, y1) and (x2, y2), which in this case is (1, 6) and (3, 10)
(Doesn't matter which is which but you need to make sure that once you decide which is which, you stick to it)
To calculate the gradient, you substitute these values following (y1 - y2)/(x1 - x2)
Gradient of function 2 = (10 - 6)/(3 - 1)
= 2
Therefore, since 4 > 2, rate of change of function 1 > rate of change of function 2.
Answer:
I'm pretty sure its b but I'm not sure I'm sorry if it's wrong
Let's give some distances
100 up 100 flat 100 down meters
then return 100 up 100 flat 100 down
time required (distance/rate = time ) 200/100 + 200/120 + 200 / 150 = 5 hr
distance 600
distance / time = average speed = 600/5 = 120 m/s