The way to distribute the eggs at the lowest cost would be using 5 cartons of 12 eggs and 1 carton of 6 eggs.
Since Timmy is helping his grandpa on his chicken farm, and he has to pack 66 eggs into cartons, minimizing the packing cost, and he can use 12-egg cartons and 6-egg cartons, and two 12-egg cartons cost as much as three 6-egg cartons, to determine how many cartons of each should be used, the following calculation must be performed:
- 2 x 12 = 3 x 6
- 24 = 18
- Thus, assuming as an example that a total of 2 cartons of 12 eggs and 3 cartons of 6 eggs cost $ 3, the value of each carton would be the following:
- 3/3 = 1
- 3/2 = 1.5
- 66/12 = 5.5
- 5 x 1.5 + 1 x 1 = X
- 7.5 + 1 = X
- 8.5 = X
In this way, the way to distribute the eggs at the lowest cost would be using 5 cartons of 12 eggs and 1 carton of 6 eggs.
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<h3>
Answer: 9,979,200</h3>
This is one single number. It's just a bit under 10 million
Delete the commas if necessary.
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Explanation:
If we could tell the repeated letters apart, then there would be
11*10*9*8*7*6*5*4*3*2*1 = 39,916,800
different ways to scramble up the letters.
However, we have 2 copies of b and 2 copies of i
So we have to divide by 2*2 = 4 to correct this overcounting
(39,916,800)/4 = 9,979,200
Answer:
No ,its irrational
Step-by-step explanation:
bcoz of it is not fixed number
it is infinite number
Answer:
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27