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2 years ago

The orthocenter of a triangle is formed by the _____ of a triangle

Mathematics

1 answer:

Kryger [21]2 years ago

5 0

Its formed by the 3 altitudes

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<img src="https://tex.z-dn.net/?f=solve%20%3A%20%20-%20%20%5C%5C%20%20%5C%5C%20%282%20%5E%7B2%7D%20%20%2B%204%20%7B%7D%5E%7B2%7D

Dahasolnce [82]

$\implies {\blue {\boxed {\boxed {\purple {\sf {20}}}}}}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}$

$= ( {2}^{2} + {4}^{2} )$

$= [(2 \times 2) + (4 \times 4)]$

$= (4 + 16)$

$= 20$

$\large\mathfrak{{\pmb{\underline{\orange{Thank\:you! }}{\orange{❦}}}}}$

8 0

2 years ago

(5 + 6) - + (-5 - 6) + - (5 - - 6) A.21 B.12 C.11 D.18

lora16 [44]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Read the following statement: Line segment CD is congruent to line segment EF. Which of the following is an equivalent statement

Natasha_Volkova [10]

An equivalent statement is CD overbar congruent to EF overbar.

What is a line segment?

The line segment has two fixed-length endpoints, A and B. The distance between this line segment's endpoints A and B is its length.

Here,

Line segment CD is congruent to line segment EF and in geometry, an overbar represents a line segment.

So, we can say that the CD overbar means line segment CD and the EF overbar means line segment EF.

Hence, An equivalent statement is CD overbar congruent to EF overbar.

To learn more about the line segment from the given link

brainly.com/question/17374569

#SPJ1

7 0

1 year ago

Solve the solution. How many solutions does it have? 4(2x-3)=2(4x-6)

sdas [7]

Answer:

No solutions

Step-by-step explanation:

4(2x-3)=2(4x-6)

$4(2x-3)=2 \times 2(2x-3) \\ \\ 4(2x-3)=4(2x-3)$

Same components are present on both sides of equal sign, therefore NO SOLUTIONS are possible.

7 0

3 years ago

Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.

torisob [31]

Fermat's little theorem states that
$a^p$ ≡a mod p

If we divide both sides by a, then
$a^{p-1}$ ≡1 mod p
=>
$a^{17-1}$ ≡1 mod 17
$a^{16}$ ≡1 mod 17

Rewrite
$a^{1000000}$ mod 17 as
$=(a^{16})^{62500}$ mod 17
and apply Fermat's little theorem
$=(1)^{62500}$ mod 17
=>
$=(1)$ mod 17

So we conclude that
$a^{1000000}$ ≡1 mod 17

6 0

3 years ago