A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375
Answer:
Zero real roots:
f(x) = x^2-x+1
f(x) = x^2+2x+3
One real root:
Two real roots:
f(x)=x^2+2x+1
f(x)=x^2-3x+2
Step-by-step explanation:
These were determined by using the quadratic formula.

From Left side:


NOTE: sin²θ + cos²θ = 1






Left side = Right side <em>so proof is complete</em>
Answer:
x = 
Step-by-step explanation:
Using the Altitude- on- Hypotenuse theorem
(leg of Δ ABC )² = (part of hypotenuse below it ) × ( whole hypotenuse )
x² = 3 × (3 + 7) = 3 × 10 = 30 ( take the square root of both sides )
x = 
Subtract a number from the next number.
39 - 45 = -6
Answer: B. -6