Answer:
B. 39.59
Step-by-step explanation:
So 43 degrees, you know the length of the opposite side (27) and the angle (43 degrees), the only unknown is the hypotenuse. So you're looking for a trigonometric ratio that uses the angle (all of them do, except technically the inverse don't), the opposite side, and the hypotenuse. Sine is defined as
. So let's plug in known values:
![sin(43) = \frac{27}{x}](https://tex.z-dn.net/?f=sin%2843%29%20%3D%20%5Cfrac%7B27%7D%7Bx%7D)
Multiply both sides by x
![sin(43) * x = 27](https://tex.z-dn.net/?f=sin%2843%29%20%2A%20x%20%3D%2027)
divide both sides by sin(43)
![x=\frac{27}{sin(43)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B27%7D%7Bsin%2843%29%7D)
Normally I would use a calculator, but in this case I'll use the approximation given in the problem of 0.682
![x=\frac{27}{0.682}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B27%7D%7B0.682%7D)
simplify the fraction
![x\approx39.59](https://tex.z-dn.net/?f=x%5Capprox39.59)
Assuming -5 is m
y-3 = -5 (x + 7)
y - 3 = -5x - 35
y = -5x - 33
hope this helps , give brainliest.
Answer:
x = 55
Step-by-step explanation:
opposite angles are supplementary
125+x = 180
Subtract 125 from each side
125+x-125 = 180-125
x = 55
Answer:
let's see what to do buddy...
Step-by-step explanation:
![\frac{zinc}{copper} = \frac{3}{17} \\ \\ \frac{zinc}{799} = \frac{3}{17}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bzinc%7D%7Bcopper%7D%20%3D%20%20%5Cfrac%7B3%7D%7B17%7D%20%5C%5C%20%20%5C%5C%20%20%5Cfrac%7Bzinc%7D%7B799%7D%20%3D%20%20%5Cfrac%7B3%7D%7B17%7D%20%20%20%20)
Multiply the sides of the equation by 799
![zinc = \frac{3}{17} \times 799 \\ \\ zinc = \frac{3}{17} \times 17 \times 47 \\ \\ zinc = 3 \times 47 = 141](https://tex.z-dn.net/?f=zinc%20%3D%20%20%5Cfrac%7B3%7D%7B17%7D%20%5Ctimes%20799%20%5C%5C%20%5C%5C%20zinc%20%3D%20%20%5Cfrac%7B3%7D%7B17%7D%20%5Ctimes%2017%20%5Ctimes%2047%20%5C%5C%20%5C%5C%20%20zinc%20%3D%203%20%5Ctimes%2047%20%3D%20141%20%20)
So A jar of the chemical contains 141 grams of <em><u>zinc</u></em>.
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer:
Parallel segments → 1
perpendicular segments → 2
congruent segments → 3
![---------](https://tex.z-dn.net/?f=---------)
hope it helps...
have a great day!!