9514 1404 393
Answer:
671 feet
Step-by-step explanation:
There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².
v² = 2ad
d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft
This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...
max height = 95 ft + 576 ft = 671 ft
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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...
h(t) = -16t^2 +192t +95
The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:
t = -(192)/(2(-16)) = 6
Then the maximum height is ...
h(6) = -16·6^2 +192·6 +95 = 671
The maximum height is 671 feet.
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<em>Additional comment</em>
For the standard-form quadratic ...
y = ax^2 +bx +c
The axis of symmetry is ...
x = -b/(2a)
To work out the mean of a data set add all the numbers together and divide them by the number of data items there are.
18 + 14 + 8 + 22 + 25 + 8 = 95
95/6 = 15.8 (that answer is rounded)
You use the formula Interest=principle (rate) time or i=prt. If you use that formula to solve, your answer will be 3,500. After five years, the balance will be $3,500.
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Slope-Intercept Form: y=mx+b
Standard Form: ax+by=c
Point- Slope: (y-y1)= m(x-x1)
There are multiple answers to your question-
- If you are only missing b(the y-intercept) but are given a set of points, plug the points into x and y and solve for b.
- If you are only missing the slope(m) but are given a set of points, plug the points into x and y and solve for m.
- If you are given the standard form/point-slope form, change the equation to slope intercept form.
- If you are given an complete form(there is an x and y; no missing variables), but are not sure what it is, plug in some numbers in x to find y, then graph.