<u>(83.9 × 10^12)(2.87 × 10^-³)</u>
3.76 × 10²
<u>(83,900,000,000,000)(0.00287)</u>
376
<u>240,793,000,000</u>
376
640,406,914.9
Answer:
Step-by-step explanation:
- Total number of bikes = 18
- Bikes with gears S = 9
- Bikes with suspension S = 11
- Bikes with both GS = 5
<u>From the information above we have:</u>
- Bikes with gears only = 9 - 5 = 4
- Bikes with suspension only = 11 - 5 = 6
<u>Sum of the above two gives us the number of bikes with suspension or gears:</u>
<u>Probability of selected bike be G or S is:</u>
S represents the best distance from 1 and 0 to represent 33 1/3%
Answer:
The required function is:
Step-by-step explanation:
We have to represent the given scenario as an equation or function
Let x be the number of miles driven in a week
Let C(x) be the function of the number of miles driven
As it is given that charges are 150 per week, these charges are constant so they will be used as it is.
It is also given that the cost of car is 0.45 per mile so for x miles the cost will be:
0.45x
Combining both terms, we get
Hence,
The required function is:
9514 1404 393
Answer:
64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Step-by-step explanation:
The row of Pascal's triangle we need for a 6th power expansion is ...
1, 6, 15, 20, 15, 6, 1
These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.
Your expansion is ...
1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...
15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6
= 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
