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MrMuchimi
3 years ago
5

Simplify the question 18x - 6x + 2x

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0
To common number is 2 to divide all of them to 2
9x - 3x + x
6x + x
the simplified answer is 7x
You might be interested in
If four pounds of a certain candy cost $10 how many pounds of that candy can be purchased for $12
Mama L [17]
4.8 pounds, set it up as 4 over 10 times x over 12, to find x multiply 4 by 12, and divide by ten. The result is 4.8
3 0
3 years ago
2.6 I’m a improper fraction
slavikrds [6]

Answer:

26/10 is your answer

Step-by-step explanation:

2 6/10 = 26/10

2 is your whole and 6 is your numerator and 10 is your denominator since 6 is in the TENTHS place.

8 0
3 years ago
The final margin of an NFL football game is approximately normally distributed, with a mean equal to the gambling point spread a
nika2105 [10]

Answer:

The Giants had 0.1949 = 19.49% probability of winning initially.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean equal to the gambling point spread and a standard deviation of 14 points. The Patriots had been favored by 12 points.

This means that \mu = 12, \sigma = 14

What does that fact imply about the Giants' initial (i.e., pre-game) chances of winning

P(X > 0): Probability of Patriots winning.

P(X < 0): Probability of Giants winning.

So we want to find P(X < 0), which is the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - 12}{14}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

The Giants had 0.1949 = 19.49% probability of winning initially.

7 0
3 years ago
90$%097910 •=09462910 =
notka56 [123]
0.473892783..........

5 0
3 years ago
52 is 13% of what number
pentagon [3]
I believe the answer would be 400
because if you divide 52/0.13 you get 400
3 0
3 years ago
Read 2 more answers
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