3 years ago

The dot plots show the forearm lengths of 2 groups of 10 students. What statements could be true

Mathematics

1 answer:

andriy [413]3 years ago

6 0

B. Is the answer because group a has a greater variability then group b

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47.9 less than k is -21.6

Law Incorporation [45]

K is equal to -69.5 K=69.5 You put it in an equation 47.9-K=-21.6Then you subtract 47.9 from both sides and you get K=69.5

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3 years ago

Ariela is selling tickets to a play. adult tickets cost $12.25 and children's tickets cost $8.75. the total amount of money she

Romashka [77]

12.25x + 8.75y > = 90 (thats greater then or equal) <== ur inequality

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3 years ago

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Shannon wants to buy cupcakes for her friend's birthday party. The bakery she goes to sells cupcakes for $3.50 each. The bakery

Aleks [24]

So I think it would be $35 because if you multiply $3.50 by ten then it would be $35

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3 years ago

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I need to know the answer

solniwko [45]

X-3/8=-1/4
+3/8
x=-1/4+3/8
make both bottom numbers the same so you are able to add them
-1/4×2/2= -2/8
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3 years ago

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5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls

miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = $cos^{2}x - sin^{2}x$

2. Pythagorean identity:

$cos^{2}x + sin^{2}x = 1$

Back to your problem, replacing the variable by the above:

$5cosx-sin\frac{x}{2}+7 = 0$

$5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Double-angle formula

$5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Pythagorean identity

Given $y = \frac{x}{2}$

$5(1-2sin^{2}y) - 2siny + 7 = 0$

$10sin^{2}y+2siny-12=0$

$5sin^{2}y+siny-6=0$

$(5siny + 6)(siny - 1)=0$ , we know -1 < sinx < 1, for every x ∈ R

$siny = 1, y =90$

$y = \frac{x}{2}$

$x = 180$

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2 years ago