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ololo11 [35]
3 years ago
12

How do you solve 39 equal to 1 3/10b

Mathematics
1 answer:
elena-s [515]3 years ago
5 0
If 39 = (1 3/10)b, we could simplify this by writing 39 - (13/10)b.

Solve this for b by mult. both terms by (10/13):

(10*39)
----------- = (10/13)(13/10)b.  Then b = 30 (answer)
      13
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An evergreen nursery usually sells a certain shrub after 5 years of growth and shaping. The growth rate during those 5 years is
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Answer:

h(t) = 0.75t^2 + 4t + 12

Step-by-step explanation:

The equation given calculates the derivative of the height in relation to the time, that is, the rate of change of the height. To find the equation for the height, we need to integrate this equation:

dh/dt = 1.5t + 4

Multiplying both sides by 'dt', we have:

dh = (1.5t + 4)dt

Using the integral in both sides:

\int dh = \int (1.5t + 4) dt

h = 0.75t^2 + 4t + h(0)

h = 0.75t^2 + 4t + 12

So the height after t years is represented by this equation:

h(t) = 0.75t^2 + 4t + 12

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Step-by-step explanation:

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Answer:

a\cdot b=-2000\sqrt{2}

Step-by-step explanation:

Given information: |a| = 80, |b| = 50, the angle between a and b is 3π/4.

We need to find the dot product  a · b.

The formula of dot product is

a\cdot b=|a||b|\cos \theta

where, θ is the angle between a and b.

Substitute the given values in the above formula.

a\cdot b=(80)(50)\cos (\frac{3\pi}{4})

a\cdot b=4000\cos (\pi-\frac{\pi}{4})

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a\cdot b=-4000\frac{1}{\sqrt{2}}

a\cdot b=-\frac{4000}{\sqrt{2}}

Rationalize the above equation.

a\cdot b=-\frac{4000}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}

a\cdot b=-\frac{4000\sqrt{2}}{2}

a\cdot b=-2000\sqrt{2}

Therefore, the value of a · b is a\cdot b=-2000\sqrt{2}.

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