The equation would be 63500-700x=P, where 63500 is the original population, -700 is the amount the population decreases each year, x is the number of years, and P is the total population.
To answer the second part of the question, plug in 53000 for P and solve for x:
63500-700x=53000
<em>*Subtract 63500 from both sides*</em>
-700x=-10500
<em>*Divide both sides by -700*</em>
x=15
It would take 15 years for the population to drop to 53000.
The equation has oneextraneous solution which is n ≈ 2.38450287.
Given that,
The equation;
We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has oneextraneous solution which is n ≈ 2.38450287