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Kobotan [32]
3 years ago
8

E. coli cells grown on 15n medium are transferred to 14n medium and allowed to grow for two more generations (two rounds of dna

replication). dna extracted from these cells is centrifuged. what density distribution of dna would you expect in this experiment?
e. coli cells grown on medium are transferred to medium and allowed to grow for two more generations (two rounds of dna replication). dna extracted from these cells is centrifuged. what density distribution of dna would you expect in this experiment?
Biology
1 answer:
Pie3 years ago
3 0
The density distribution that one will expect from this experiment is ONE LOW DENSITY AND ONE INTERMEDIATE DENSITY BANDS.
The 14N  and the 15N media are refereed to as light and heavy medium respectively, they are composed of isotopes of nitrogen. When growing on the 15N medium, the E coli takes part of the nitrogen isotope and use it to make new biological molecules including DNA. The same thing happens when the E coli was put in the 14N media. Density gradient centrifugation is then used to measure the density of the DNA, thus, indirectly measuring the 15N and the 14N components of the DNA. 
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Consider the atps that can be generated via substrate-level phosphorylation. Will glycolysis be useful for generating any atps d
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Indeed, glycolysis would be useful for creating ATP as it produces a net increase of ATPs. One glucose particle produces two ATP in a cycle. On the off chance that the ETPUM experiences the procedure of aging, at that point the natural atoms would then be able to be used as the essential electron transporter. Two ATPs would be delivered by means of TCA cycle and yes it will be sufficient to help development.  

Further Explanation:  

Phosphorylation:  

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Subject: biology

Level: college

Keywords: Phosphorylation, ATP,ATP utilized for,  TCA.

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Answer:

DNA Replication:

Replicate the following strand of DNA:

Original DNA: A T G A A C CA T T C A G T A T G G

Complementary DNA:

Remember that the complimentary base pairs in DNA are Adenine-Thymine and Guanine-Cytosine, or A-T and G-C. This means that if the original sequence is:

A T G A A C C A T T C A G T A T G G

Then the compliment is (replace with the opposite base pairs):

T A C T T G G T A A G T C A T A C C

Transcription:

Transcribe the DNA to make an mRNA molecule

COMPLIMENTARY DNA:

mRNA Molecule:

So if our complimentary DNA (antisense stand) is T A C T T G G T A A G T C A T A C C then to transcribe, we basically create another complimentary strand, but for mRNA, we use Uracil instead of Thymine:

A U G A A C C A U U C A G U A U G G  

Translation:

Translate the mRNA into the corresponding amino acids.

mRNA MOLECULE:

AMINO ACID:

Using the DNA sequence provided, determine the amino acids.

Next, take each codon (3-base set) to the table and record the corresponding protein:

A U G = Methionine (start)

A A C = Asparagine

C A U = Histidine

U C A = Serine

G U A = Valine

U G G = Tryptophan

ORIGINAL DNA: A T G G G T C T A G C G A A A G A T

Complementary DNA:

mRNA DNA Molecule:

Amino Acid:

And we do it all again:

A T G G G T C T A G C G A A A G A T = original DNA

T A C C C A G A T C G C T T T C T A = complementry DNA

A U G G G U C U A G C G A A A G A U = mRNA

A U G = Methionine (start)

G G U = Glysine

C U A = Leucine

G C G = Alanine

A A A = Lysine

G A U = Aspartate

Explanation:

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