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2 years ago

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Mathematics

2 answers:

Anettt [7]2 years ago

5 0

The answer is D because is you add a one under the 9 you get 9/1 x 2/3 and you can just multiply straight away and get 18/3 but if you need to simplify more you get 6

Illusion [34]2 years ago

5 0

Answer:

The answer is D) eighteen thirds.

Step-by-step explanation:

9/1 times 2/3

equals 18/3

18/3 is "eighteen thirds"

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lilavasa [31]

Answer: A

Explanation:
First you have to write the model in an equation form.

6x+5=15

Subtract 5 from both sides

6x=10

Divide 6 from both sides

X=10/6

Simplify

X=5/3 or 1.67

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2 years ago

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Evaluate-a-function f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B7%7D" id="TexFormula1" title="\frac{x}{7}" alt="\f

OLga [1]

Step-by-step explanation:

Hey there!

f(x) = 7/x

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2 years ago

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Ramon has $2,340 in his saving account. Write an expression for the amount in his account after he deposits d dollars and withdr

sertanlavr [38]

1270 I Hope This Is Correct

3 0

3 years ago

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A donut machine makes small glaze donuts the diameter of each doughnut is 8 cm. What is the circumference of each doughnut creat

kotegsom [21]

Answer:

50.29 cm

Step-by-step explanation:

Given:

Diameter of each doughnut = 8 cm

To find: circumference of each doughnut

Solution:

Circumference refers to the boundary of a geometric figure.

A doughnut has the shape of a circle.

Let r represents the radius of the circle.

Diameter of each doughnut = 8 cm

Radius of each doughnut (r) = Diameter/2

$=\frac{8}{2}\\ =4 \,\,cm$

Circumference of each doughnut $=\pi r^2\\$

Put $r=4\,\,,\pi=\frac{22}{7}$

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4 0

3 years ago

The nth term of a sequence is 3n^2- 1

Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √( (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √( (31 - 2^2)/3) = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0

2 years ago