Question

Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3).

Answer 1

Answer:

A) y = − 1 /5 x +  16/ 5

Step-by-step explanation:

Answer 2

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x + 5y = 10 into this form

Subtract x from both sides

5y = - x + 10 ( divide all terms by 5 )

y = - $\frac{1}{5}$ x +2 ← in slope- intercept form

with slope m = - $\frac{1}{5}$

• Parallel lines have equal slopes, hence

y = - $\frac{1}{5}$ x + c ← is the partial equation of the parallel line

To find c substitute (1, 3) into the partial equation

3 = - $\frac{1}{5}$ + c ⇒ c = $\frac{16}{5}$

y = - $\frac{1}{5}$ x + $\frac{16}{5}$ ← equation of parallel line