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4 years ago

9

Answer is

1 answer:

MakcuM [25]4 years ago

4 0

Answer:

Nbbd

Step-by-step explanation:

it is always the first 4 letters

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Use the line tool to graph the equation on the coordinate plane.<br><br> y=−2x

sertanlavr [38]

Hey there,

Your answer would be in the attachment above.

Hope this helps.

~Jurgen

(Any questions?, Just comment below) =)

5 0

3 years ago

Read 2 more answers

Please answer the question from the attachment.

DIA [1.3K]

There's a 8ft. long board and the carpenter cut off 3 1/2 and 2 1/3.

So first we need to add 3 1/2 and 2 1/3 because the carpenter cut them off the 8ft. long board.

3+2=5 because it's a whole number. 1/2+1/3= 2/6+3/6= 5/6
5 5/6

Now we subtract
8-5 5/6=
7 6/6- 5 5/6= 2 1/6ft.
2 1/6ft. is what remains of the 8ft. board.

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4 years ago

? + (350 × 0.84) = (620 × 0.55) – √1764 2

olchik [2.2K]

Answer: The answer is going to be

120 x 65%/3

4 0

3 years ago

What is 10% of 7/8 of 160

olga55 [171]

Answer:

14

7/8of 160=140

140×10=1400

1400÷100=14

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2 years ago

The table shows a proportional relationship between the number of pounds of bananas purchased and the total cost of bananas.

Liula [17]

Answer:

Choice A, C and E

Step-by-step explanation:

<em>Your table is poorly presented</em>

Given

x y

$\begin{array}{cc} {3} & {1.47} \ \\ {5} & {2.45} \ \\ {9} & {4.41} \ \ \end{array}$

First, we calculate the constant of proportionality (k)

$k = \frac{y}{x}$

For (3,1.47)

$k = \frac{1.47}{3}$

$k = 0.49$

For (5,2.45)

$k = \frac{2.45}{5}$

$k = 0.49$

For (9,4.41)

$k = \frac{4.41}{9}$

$k = 0.49$

From the above calculations, the constant of proportionality is 0.49.

So, the usable rows must also have 0.49 as their constant of proportionality

<u>Choice A</u>

$(x,y) = (2,0.98)$

$k = \frac{0.98}{2}$

$k = 0.49$ --- <em>This is usable</em>

<em />

<u>Choice B</u>

$(x,y) = (7,4.45)$

$k = \frac{4.45}{7}$

$k = 0.64$ --- <em>This is not usable</em>

<em />

<u>Choice C</u>

$(x,y) = (6,2.94)$

$k = \frac{2.94}{6}$

$k = 0.49$ --- <em>This is usable</em>

<em />

<u>Choice D</u>

$(x,y) = (1,0.54)$

$k = \frac{0.54}{1}$

$k = 0.54$ ---- <em>This is not usable</em>

<em />

<u>Choice E</u>

$(x,y) = (8,3.92)$

$k = \frac{3.92}{8}$

$k = 0.49$ --- <em>This is usable</em>

5 0

3 years ago