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Alex73 [517]
3 years ago
11

Find the value of 3x 5(2)

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

is it 30?

Step-by-step explanation:

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ritu can row downstream 20km in 2 hrs and upstream 4km in 2 hrs. find the speed of rowing in still water and the speed of the cu
Marina CMI [18]

Answer:

Speed of boat in still water is 6km/h

Speed of current is 4km/h

Step-by-step explanation:

We know speed = distance / time

Let the speed of boat in still water be x

Let the speed of current be y

Hence the speed of boat, down stream = x+y

Distance downstream = 20km

Time taken = 2 hours

We have

x+y=\frac{20}{2}

x+y=10       ......(1)

Speed of boat upstream = x-y

Distance upstream = 4

Time taken = 2

We have

x-y=\frac{4}{2}

x-y=2    ...(2)

Adding (1) & (2)

2x=12

x=6

Substituting in (1) we get

y=4

7 0
3 years ago
HELP ME OUT FOR FIVE POINTS PLEASE I WILL RATE YOU BRAINLIEST
Lemur [1.5K]
X = 2 because 2+1=3 and if you want 5 then 5 - 3 = 2 so x=2
8 0
4 years ago
Read 2 more answers
Which of the following statements best describes the value of the expression 2x + 12, when x = 3?
Lapatulllka [165]
The answer to the equation is 18 which is a composite whole number. the answer is C
4 0
3 years ago
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two trains leave the station at the same time, one heading west and the other east. the westbound train travels at 80 miles per
jekas [21]

Answer:

let this happens after t hours

so

80t + 60t = 392

140 t = 392

t = 392/140

=2.8 hours

3 0
3 years ago
Read 2 more answers
find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho
____ [38]
For a quadratic of the form f(x)=ax^2+bx+c, we have the quadratic formula 
x=\dfrac{-b \pm \sqrt{b^2 -4ac}  }{2a},
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given 2x^2-16x+27=0, we can get that a=2, \ b=-16, and c=27. We substitute these numbers into the quadratic formula above.

x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}

x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}

x=\dfrac{16 \pm \sqrt{40} }{4}

x=\dfrac{16 \pm 2\sqrt{10} }{4}

x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the \pm symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.
8 0
4 years ago
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