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2 years ago

Graph the linear inequality. x + 2y = 5

2 answers:

8 0

we can graph the linear function by finding first the x and y intercepts.
x-intercept
x + 0 = 5; x =5P ( 5,0)
y-intercept0 + 2y = 5y = 5/2P(0,5/2)
We connect the two points and extend the line infinitely

choli [55]2 years ago

5 0

So you always want y in front of the equation no matter what so you have x +2y=5 so you take the x and you subtract it to both side making it 2y= 5-x so then you just have to take the 2 to both side so you have to divide it and you will get y= 5/2-x/2 so then to graph it you start with the b which is -x/2 so you go down -1 and over 2 and place your dot adn then go up 5 over 2 and then place you dot and connect them together

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Solve the inequality 3 - 5(2x + 1) 10.

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3 - 50(2x + 1)
3 - 100x - 50
-100x + (3 - 50)
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2 years ago

Which of the following steps would you perform to the system of equations below so that the equations have equal x-coefficients?

12345 [234]

The answer is A. Multiply both sides of the top equation by 2

So since we know that 4 × 2 = 8, it would only make sense to multiply both sides by 2 so that the top equation has the x coefficient be 8.

5 0

3 years ago

Read 2 more answers

What is the difference between solving inequalities from equations

AVprozaik [17]

Answer:

An equation is a mathematical statement that shows the equal value of two expressions while an inequality is a mathematical statement that shows that an expression is lesser than or more than the other. 2. An equation shows the equality of two variables while an inequality shows the inequality of two variables.

4 0

1 year ago

The graph of r = -10 cos θ has which of the following characteristics?

Ronch [10]

Step-by-step explanation:

If we convert

$r = - 10 \cos(x)$

to a Cartesian equation,

${r}^{2} = - 10 r \: \cos(x)$

${x}^{2} + {y}^{2} = - 10x$

${x}^{2} + 10x + {y}^{2} = 0$

${x}^{2} + 10x + 25 + {y}^{2} = 25$

$(x + 5) {}^{2} + {y}^{2} = 25$

So we have a circle with center (-5,0), with a diameter of 10.

8 0

1 year ago

What is cos theta when sin theta = sqrt 2/3

Fittoniya [83]

Answer:

Value of cosθ is ±√7/3 .

Step-by-step explanation:

According to the Question , value of :

$\red{\implies sin\theta = \dfrac{\sqrt2}{3}}$

And , we know the identity of sine and cosine as ,

$\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }$

Using , this identity we have ;

$\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}$

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

$\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}$

3 0

2 years ago