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Amanda [17]
3 years ago
15

Ebony body, held-out wings and sepia eyes are ALL RECESSIVE AND ALL ON CHROMOSOME 3. The COEFFICIENT of COINCIDENCE for chromoso

me 3 is 0.5. A homozygous ebony male is mated to a homozygous held out wing and sepia eyed female. The F1 are wild-type. An F1 female is test crossed to a fly that is homozygous for all three recessive alleles and they produce 1000 progeny. If ebony and held-out are separated by 12 map units, and held-out and sepia are 14 map units apart, and if the order of these loci is ebony, held-out, and sepia: How many ebony, sepia (but not held-out) progeny are expected from this test cross?
Biology
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answ.15er:

Explanation:

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