Question

Ebony body, held-out wings and sepia eyes are ALL RECESSIVE AND ALL ON CHROMOSOME 3. The COEFFICIENT of COINCIDENCE for chromosome 3 is 0.5. A homozygous ebony male is mated to a homozygous held out wing and sepia eyed female. The F1 are wild-type. An F1 female is test crossed to a fly that is homozygous for all three recessive alleles and they produce 1000 progeny. If ebony and held-out are separated by 12 map units, and held-out and sepia are 14 map units apart, and if the order of these loci is ebony, held-out, and sepia: How many ebony, sepia (but not held-out) progeny are expected from this test cross?

Answer 1

Answ.15er:

Explanation: