3 years ago

How do you solve this

Mathematics

2 answers:

gavmur [86]3 years ago

8 0

You have to times the 5 and 9 and you will get the answer to V.

kogti [31]3 years ago

7 0

Multiply 9 and 5 and you get 45.

You might be interested in

PQRS is an isosceles trapezoid and m

Otrada [13]

Answer:

i have no idea what it is so good luck

Step-by-step explanation:

3 0

3 years ago

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

2 years ago

Anyone know the answers to 10, 11, 12?

VashaNatasha [74]

10. is f 11. is a I dont know for 12 though

4 0

2 years ago

Read 2 more answers

Angela has a credit score of 800 describe reasons why her score might be so high

Lapatulllka [165]

She does not use her creator card a lot or she does not purchase many expensive items

6 0

3 years ago

What's the next three numbers in this inductive reasoning pattern<br> 10,7,4,1

pentagon [3]

10, 7, 4, 1, -2, -5, -8

3 0

3 years ago