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3 years ago

If you rewrite the problem 14(22) as 14(20+2) so that you can use mental math, which of the following properties will you use?

1 answer:

7 0

For this case, the property you can use is the following:
Commutative property.
We have then that:
14 (20 + 2) = 280 + 28 = 308
Equivalently:
14 (2 + 20) = 28 + 280 = 308
Either way the result is exactly the same.
Answer:
Commutative property.

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3 years ago

Help please help ,,,,,

Natalka [10]

Answer:

18 cm²

Step-by-step explanation:

The area labelled A is a triangle.

The area (A) of a triangle is calculated using the formula

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here b = 9 and h = 4 ( the same height as the rectangle ), thus

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3 years ago

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cestrela7 [59]

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2 years ago

A cylinder has a volume of 315π cubic meters. What is the area of the base?

zepelin [54]

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Step-by-step explanation:

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3 years ago

The National Center for Health Statistics (NCHS) reports that 70%70% of U.S. adults aged 6565 and over have ever received a pneu

Marianna [84]

Answer:

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they received a pneumococcal vaccination, or they did not. The probability of an adult receiving a pneumococcal vaccination is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.

This means that $p = 0.7$

20 adults

This means that $n = 20$

Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.

This is P(X = 12).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144$

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

3 0

3 years ago