The probability of observing a particular value of a continuous random variable ______

Which of the following statements is true ? a. 0÷15=0 b. 15-0=0 c.15+0=0 d.15÷0=0

max2010maxim [7]

A, because you if you try to divide 0 into 15 parts you get 0

4 0

3 years ago

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago

Write absolute value of the following rational number -6/11 , 15/21 , -9 , -21/-37 , 31/-54

Dahasolnce [82]

Answer:

6/11, 15/21, 9, 27/37, 31/54

Step-by-step explanation:

Absolute value is when you determine the distance between a value and zero . Since you will always have a positive distance, your absolute values are positive as well.

4 0

3 years ago

Which one is lower 31.54 for 2 hours or 43.96 for 3.5 hours

pychu [463]

The answer would be 43.96 for 3.5 hours because for each hour it's 12.56

7 0

3 years ago

Complete the remainder of the table for the given function rule:

USPshnik [31]

answer is

(Y)=-23,-14, -5,4,13

hope this will help you

3 0

3 years ago

The probability of observing a particular value of a continuous random variable​ _______.

The probability of observing a particular value of a continuous random variable _______.