We use the equation for repeated trials written below:
Probability = n!/r!(n-r)! * p^(n-r) * q^r
The p is the probability of getting a side A in one toss. Since a counter has only two side, p = 0.5. The q is the probability of not getting side A in one toss, which is also q = 0.5. Now, r is the number of success per n trials. There are 3 tosses so, n=3. The question is getting "at least 1" counter. So, r=1, r=2 and r=3.
Probability for r=1: 3!/1!(3-1)! * (0.5)^(3-1) * (0.5)^1= 0.375
Probability for r=2: 3!/2!(3-2)! * (0.5)^(3-2) * (0.5)^2= 0.375
Probability for r=1: 3!/3!(3-3)! * (0.5)^(3-3) * (0.5)^3= 0.125
Total probability = 0.375 + 0.375 + 0.125 = 0.875
Answer:
youngest 17
middle 19
oldest 21
Step-by-step explanation:
Three sisters have ages that are consecutive odd integers
youngest = x
middle = x + 2
oldest = x + 4
--------------------
The sum of the age of the youngest
x
and three times the age of the oldest
+ 3(x + 4)
is five less than five times the middle sister’s age
= 5(x + 2) - 5
-----------------------
x + 3(x + 4) = 5(x + 2) - 5
Distribute
x + 3x + 12 = 5x + 10 - 5
Combine like terms
4x + 12 = 5x - 5
Subtract 4x from both sides
12 = x - 5
Add 5 to both sides
17 = x
youngest x = 17
middle x + 2 = 19
oldest x + 4 = 21
Answer:
I'm pretty sure it's the to right one
Step-by-step explanation:
Just multiply 10*3*2 and the answer is 60 cm^3
Answer:
Step-by-step explanation:
To calculate the 99th percentile you must order scores from least to greatest, and the one that occupies the position that corresponds to 99% of n-scores is the 99th percentile.
The 99th percentile of a set of observations ( in this case, exam scores) is a value such that 99% of the observations are less than or equal to him and the remaining 1% is greater than or equal to him.
If he is now in the 84% is because there are some people that took the exam in February that are better than him, they had better scores and then, 84% of the observations are less than or equal to him and the remaining 16% is greater than or equal to him.
Before there were only 1% scores that were better than his or her score. Now, there are 16% scores that are better, then people got better scores in the February exam, compared to your friend's score.
