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4 years ago

Please Help! Which equation of a line of best-fit reflects a negative correlation?

Mathematics

2 answers:

12345 [234]4 years ago

8 0

Answer:

y=-6x+13

Step-by-step explanation:

Lisa [10]4 years ago

7 0

Its the last one i think

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52 > 43 + w

zvonat [6]

Hopes this helps

Answer: w < 9 yes

Please mark as brainlist

4 0

3 years ago

What is the value of x? A.86 B.60 C.52 D.26

Nadya [2.5K]

First of all in order for us to figure out what angle x is we need to find the formula for finding that specific type of angle.

Formula is...

x = (far arc - close arc) ÷ 2

Now we just need to plug in.

x = (172° - 52°) ÷ 2 =

x = 120° ÷ 2 = 60°

Your answer: x = 60°

Good Luck! :)

❤️ ❤️ ❤️

6 0

3 years ago

The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?

BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
$A_{n}=A_{1}+(n-1)d$

$A_{n}$ is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so $A_{1}=47$
d=-2 because the question gives you that

$A_{n}=A_{1}+(n-1)d$
 $A_{29}=47+(29-1)(-2)$
 $A_{29}=47+(28)(-2)$
 $A_{29}=47+-56$
 $A_{29}=-9$

The answer is A. -9.

 

The answer is C. 158

For the second one, it gives you $A_{1}=4$ and $A_{}=18$
You can use this to find d

 $A_{n}=A_{1}+(n-1)d$
 $A_{3}=4+(3-1)d$
 $18=4+(3-1)d$
 $18=4+2d$
 $14=2d$
 $7=d$

Now you can just solve using the equation normally.
 $A_{n}=A_{1}+(n-1)d$
 $A_{23}=4+(23-1)(7)$
 $A_{23}=4+(22)(7)$
 $A_{23}=4+154$
 $A_{23}=158$

The answer is C. 158

8 0

4 years ago

Read 2 more answers

Evaluate the expression. 8 + 12 • 7

arsen [322]

Multiply first, then add. 12 times 7 = 84. Then add 8. 84 + 8 = 92.

5 0

4 years ago

Read 2 more answers

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

Read 2 more answers