Question

When you roll two number cubes, what are the odds in simplest form against getting two numbers greater than 3?

Answer 1

Option B

When you roll two number cubes, the odds in simplest form against getting two numbers greater than 3 is 1 : 4

Solution:

The probability of an event is given as:

$\text {probability of an event }=\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}$

Given that,

Tow number cubes are rolled

To find: Probability of getting two numbers greater than 3

On a number cube there are 6 numbers {1, 2, 3, 4, 5, 6} Out of which 3 numbers are greater than 3 {4, 5, 6}

So, total number of possible outcomes = 6

Favourable outcomes = number greater than 3 = 3

When you roll one number cube, probability of getting number greater than 3:

$\text { Probability (number greater than } 3 \text { ) }=\frac{3}{6}$

When you roll two number cubes, probabilty is given as:

$\text { Probability (number greater than }3)= \frac{3}{6} \times \frac{3}{6}=\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

$Probability = \frac{1}{4}$

In ratio form we can write as 1 : 4

Option B is correct