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SIZIF [17.4K]
3 years ago
15

What is the answer? 3(x-5)+2(x-1)

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0
3x-15+2x-2
=5x-17
use the distribution property
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coldgirl [10]

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0.0 hold on

Step-by-step explanation:

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If
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Answer:

0

Step-by-step explanation:

We have the two functions:

f(x)=\sqrt{x}+12\text{ and } g(x)=2\sqrt{x}

And we want to find (f-g)(144).

This is the same thing to f(144)-g(144).

So, let’s determine the value of f(144) and g(144) first:

\begin{aligned} f(144)&=\sqrt{144}+12 \\ &=12+12 \\ &=24\end{aligned}

And:

\begin{aligned} g(144)&=2\sqrt{144} \\ &=2(12) \\ &=24 \end{aligned}

Hence:

\begin{aligned} (f-g)(144) &= f(144)-g(144) \\ &=24-24 \\ &=0 \end{aligned}

Our final answer is 0.

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What is the sum of the first six terms of the geometric series?
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Step-by-step explanation:

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3 years ago
a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect
PolarNik [594]

Number of dimes were 81 and number of quarters were 47

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

<em><u>Given that There are 128 coins in all</u></em>

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

<em><u>Also given that collection of dimes and quarters is worth $19.85</u></em>

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

d \times 0.10 + q \times 0.25 = 19.85

0.1d + 0.25q = 19.85  -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

d = 128 - q -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

<h3>q = 47</h3>

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

<h3>d = 81</h3>

Thus number of dimes were 81 and number of quarters were 47

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One day at school you make the observations that kids in 12th grade are taller than kids in 9th grade. What does this illustrate
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Answer: B correlation

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